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Gandalf

demotivational posters

Gandalf
Won’t even take s**t from math.

Submitted by: dunno source via deMotivational Builder

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  1. Tfad says:

    OMG FIRST. Also, this pic is absolutely awesome.

  2. Rory says:

    First!
    Gandalf rules…

  3. julie says:

    Dear whoever made this:

    Thanks for my first real belly laugh of the day.

    Love, Julie

  4. Darakna says:

    This is so FTW!!! it blows all other’s away! XDDD

  5. DrPluton says:

    I’m surprised this wasn’t done on xkcd. It’s right up his alley.

  6. Travis says:

    If you use that answer, neither will you.

  7. hamstap85 says:

    ah, but it being sneaky, it expands all the way around infinity, never touching the x-coordinate of his staff, and continues without harm :)

    • AJAX says:

      haha i was thinking that too, it just snuck out from the bottom

      • person says:

        You get that result by putting “y=some number/x” into a graphing calculator. If x is zero, you get an error, because you can’t divide by zero, and zero is where the x-axis is. Therefore, the x axis is never touched, even though it gets so darn close.

        • strykr says:

          but you also have to think, 0 in this case is the intercept of X/Y, which in this case means that X has a certain intercept amount while Y technically in this case with Gandalf’s staff being located on the X-axis and never crossing the Y-axis means that Y=0 whereas X=where ever the staff crosses along with the X intercept along that slashed line which is kinda weird seeing as to how the staff is full whereas the rest of the line is slashed… but, still cool…

          • baconfoot says:

            It’s a vertical asymptote. The just as the function will never touch the x axis, it will also never PASS though x = whatever value the slashed line equals.

  8. FutonLife says:

    Why do people always say first? even if they are like 4th?? What does it even matter.
    Funny Pic Tho

    • MLD says:

      I can’t answer the first part of that, except perhaps their lives have so little validation that they need this (useless) achievement.

      The second part, I have some idea. I will post a comment (an actual comment, making no mention of being first) to a post, with NO OTHER comments posted. Come back the next day, there’s 1, 2, even 5 comments posted before mine. Moderation queues suck.

    • Justin says:

      because they are little kids and little kids do annoying things like that. I would not be surprised to find out that 90% of “firsters” are in 7th grade or below.

  9. Elliott says:

    Is Balrog a negative value because he has such a negative personality?

  10. questioner says:

    what is written underneath?
    [i dont get it even though i've seen lotr twice =/]

    • Psilence says:

      It’s a math joke, too. The graph has an asymptote, which is pretty much line that the graph approaches, but doesn’t actually reach. So, the graph cannot pass the asymptote, which is represented by Gandalf’s staff.

      I’m definitely NOT a math whiz, so, if that wasn’t very clear, I’m sorry, maybe someone else can explain it better.

      • Psilence says:

        Also, what is written underneath looks like
        “y=x^balrog
        Domain=(illegible, I think it’s Mines, but I really have no idea) [Walls of Moria, Bridge of Khazad Dun]
        Range=All Real #s when x=/=Gandalf”

        • -Ryo- says:

          I think it’s

          Domain = Moria [Walls of Moria, Bridge of Khazad Dun]

          Being the Walls of Moria and the Bridge of Khazad Dun its extremes.

      • questioner says:

        but but but…
        what, the paragraph is the balrog? i mean… the balrog fell down and not went up…
        and what’s with the “y=x^balrog”? that’s a Polynomial, and polynomials don’t have an asymptote…

        • questioner says:

          paragraph=graph

        • chocochook says:

          If balrog is equal to a negative number then it will make an asymptote. But still that graph would only be made from “y=-x^balrog”. This is beyond sad.. XD picking out math problems in the funniest picture I’ve seen all day…

        • no says:

          no, it’s x raised to the balrog. that’s what that “^” means. “x^balrog” is a single term, not two separate terms.

        • lyricmezzosoprano says:

          On the contrary, after Gandalf and the Balrog fought in the depths of Moria, they fled towards a high mountain peak, did they not?

        • The Hurocrat says:

          They do if they have a negative exponent. Also, this is a monomial, not a polynomial. Same principle, though.

  11. IIAOPSW says:

    im suprised no one pointed this out. that equation does not produce that graph. (i’m going to assume blarg is a constant).

    a more plausable equation for this is
    1/(x+blarg)
    although we can’t be certian since the axis are not labeled. if my equation is correct, it means that blarg<0.

  12. biggles1 says:

    note to generals,
    tan graph can flank enemies without actually going around them…

  13. Tamugetsu says:

    Hey, Gandalf. Nice work on those horizontal and diagonal asymptotes.

  14. Willster says:

    pffft, more like

    y = (x-balrog)^-1

  15. Ivory says:

    Um . . . It says in the picture that it’s Merlin . . . but friggin’ awesome!

  16. Responder says:

    Asymptote The Gray?

  17. Daniel says:

    The correct equation is actually y = 1/(x – Gandalf), asumming Gandalf is a constant. This is because the range is clearly labeled as all real numbers where x != Gandalf, which means the asymptote occurs when x = Gandalf.

    I am a math major at UCLA if anyone was wondering haha. And now I have to go study for my diff equations midterm which is in 2.5 hours =\

    • Daniel says:

      Wow, ok, I messed up. It is actually y = 1/(Gandalf – x), not the other way around. 5 points to whoever knows why!

      • chocochook says:

        Dude make it “y = (Gandalf – x) ^ balrog” where balrog is a negative value… Hell I just want balrog in there XD

      • Jamie says:

        I know why! If it were y=1/(x-Gandalf) the y values would be negative to the left of the asymptote and positive to the right of the asymptote, and the y values are positive to the right and negative to the left in the graph. Yay for math nerds!

    • Ouat says:

      Hum really ? That’s what UCLA math majors do ? Which year ?
      I’m french and i did that kind of stuff (diff equations) in the year before my final year of high school (or maybe final year, not sure anymore, it was 3 years ago)

  18. John says:

    Judging from this graph, I can conclude that balrog is negative, creating a reciprocal of x which results in an asymptote. However, x must also be negative for the graph to be to the top-left and lower-right.

    So miscalculation?

  19. Matt says:

    WHAT. I DREW THAT LIKE A YEAR AGO. I put it on Facebook and completely forgot about it! I never thought I would see it again…

    And no, the equation is not right. If I had paid attention in math class this wouldn’t exist. So yeah.

  20. Daniel says:

    Holy s**t, this is posted on a giant poster in my classroom o.o

  21. Joe says:

    actually, math doesn’t take s**t from gandalf

  22. Joe says:

    actually, math doesn’t take s**t from gandalf. to me it looks like a big fail on gandalf’s side

  23. Bob says:

    Gandalf: Divides by zero

    • Lord Ike says:

      Theoretically, if Gandalf could divide by zero, would that make this equation correct?

      • Miles says:

        The equation is y = 1 / (Gandalf – 1), so when x is Gandalf, y is 1 divided by 0. Gandalf breaks continuity because he divides by zero. Over analyzing magic math FTW!

  24. Daisy Kate says:

    i award this picture, 4000 internets.

  25. Steph says:

    This is the absolute greatest nerdy thing I’ve seen in AGES! :D

  26. mike hawk says:

    TROLLING
    nerds thinking they r cool

  27. ernie says:

    Or was that a note from the teacher?

  28. Ketzu says:

    Its nice that everyone asumes Balrog being a constant. But are Balrogs real? Are Balrogs constant? I do not think so, so it might as well be a (possibly complex) function itself!


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