BUSTED
Submitted by: James B
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BUSTED
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There goes plan A.
Plan B: Facebook
Why didn’t someone warn me my professor has a Facebook account!
LOL!
So true
niiiiceee
LOL
tl;dr
wow……………. now i put my foot in my mouth a lot, but JEEZ thats a fail. wish i could have seen that persons face
Man, you know this is a copy not only when he’s caught by his TA, but the typos even match up. I have to admit, knowing that a moron like this exists is very demotivational.
i dont get it…..
A student tried to obtain the answer for a homework question in Yahoo! Answers but a Teacher Assistant in that course (someone who helps the professor in grading, homeworks,etc. aka TA) found his post and pwnd his lazy ass.
now brett hicks, please say “thank you” to that nice mister who helped you getting the poster.
Much appreciated, jovifcp.
BTW, what makes you think I am a “mister”?
very true, very true…
Tits? Ok, since you asked nicely:
http://i.telegraph.co.uk/telegraph/multimedia/archive/01363/great-tit_1363722c.jpg
Pretty much fake.
Nobody would sign it “Your TA”.
HA HA !
http://www.chrisfinke.com/files/2008/01/nelson-ha-ha.jpg
I don’t get it, how Carbon atoms can change into Iron atoms ? Transmutation isn’t supposed to be mastered before 2143.
Nuclear transmutation is even briefly touched upon in Chem 2045C.
And apparently your knowledge of science isn’t supposed to begin until 2143.
“Difusse into”, carbon atoms enter iron’s structure to create steel.
Is not transfiguration, it is just breaking and entering.
Transmutation and diffusion are not the same thing. The question is describing individual carbon atoms moving through the iron by virtue of their kinetic energy(heat makes atoms wobble).
Diffusion: Verb: In physics, the process in which there is movement of a substance from an area of high concentration of that substance to an area of lower concentration.
The carbon atoms are more tightly packed than iron atoms, and thus will diffuse into pure iron.
Not “change into”, but “diffuse”.
When you heat iron by burning coal at a certain temperature, the carbon atoms from the coal pass into the iron ore, forming bonds with the iron. It’s part of the forging process that turns iron into steel.
Diffusion is NOT transmutation. This problem is about an alloy, which is more or less a mixture. In this case, the question is about the time it takes for the carbon atoms getting “mixed” with the iron atoms up to a certain depth. Think of gravy (carbon atoms) getting mixed into the mashed potato (iron atoms “solution”).
OWNED!!
2 years ago, due on Feb 2009?
I see a contradiction there.
THANK YOU!
Close to, after ! year they round to the closest year.
TL;DR
LoL, you are right Fries, carbon atoms can’t transmute into iron. Look carefully, it is diffusion: carbon atoms diffuse into iron i.e. carbon = solute, iron = solvent.
The dates don’t match up……. If the question was asked 2 years ago for a homework due in 2009, the asker can’t be someone in the TA’s class. Or am I missing something?
The answer was also 2 years ago.
I wonder if that guy already got his mech or mat engineering major… or changed into Liberal Arts.
It could have been assigned at the beginning of the semester (say in 2008) but the assignment wasn’t due until February.
Holy s**t . . . busted.
it’s so cute to see that nerds also hace their space on this site
He’s an engineering major, like graduate level. If he’s gotten this far and still hasn’t developed strong enough problem solving skills to figure this out for himself — and can’t even be slightly discreet in getting someone to do it for him — his career is gonna be a bust. It’s not a matter of just knowing the final answer but of understanding how to get there.
he not a graduate level engineer.. that’s a sophmore level engineering class
The problem here is the problem pictured involves plugging the given numbers into one equation and writing down the number that comes out.
Really?
D = D0 ^ (-Qd/RT)
Qd = activation energy = 137520 J/mol
T = absolute temp in Kelvin = 273 + 800 or 900
R = Gas Constant = 8.31 J/(mol*K)
distance = .1cm=.001m
time = 10 hours = 36000 seconds
D1 is (.001)^2/36000 = 2.77778e-11
log(D1) = log (D0) – (Qd/2.3R)*(1/T)
log (2.77778e-11) = log(D0) – (137520/2.3*8.31j/mol*k)*1/(273+800)
-10.5663 = log(D0) – 6.70559
log (D0) = -3.8607
D0 = 1.37814e-4
Qd/R = 137520/8.31 = 16548.73646K
Qd/2.3R = 7195.10281
t = 293+900 = 1193K
-Qd/2.3RT -6.0311
D = 1.37814e-4^-12.7987
log D2 = -3.8607 – 6.0311
= -9.8918
D2 = 1.28292125e-10 =(.001m)^2/T
T = 7794Sec = 129.91 Min = 2.165 Hours
Granted, it’s solvable, but not exactly “plug n chug” – unless you see an easier solution.
Usually, the first digit denotes the grade level. 1 is freshman, 2 is sophomore, etc. Either way, the rest of my point stands.
Geeks of the world unite!
A geek wouldn’t use yahoo answers for ANYTHING.
funny……
“well it doesn’t really matter, because once someone tells him he’s gonna learn the answer which is learning.”
that depends, if he just copies the answer to his paper, he isn’t going to learn anything. it will only help if he uses the answer given (the result, not the work leading to it) and works through the problem himself, which is doubtful if he went to yahoo answers asking instead of asking the TA directly.
Learning the answer to a specific problem isn’t the same as learning how to problem-solve. Professors care a lot more about the latter than the former. Students probably should, too.
Also, he is going to be building something I may use/ interact with if he graduates. I want him to be able to figure out himself, please!
Why is the TA googling the answer?
What’s sad is that it isn’t even a very hard question. If you are in the class you have the book. There is an equation to find diffusion at a given temp. They give you all the information to plug into the equation. So what, he can’t use a calculator?
Yeah, the equation is D = D0 ^ (-Qd/RT)
D is diffusion in meters^2/seconds,
D0 is an initial number you have to find
Qd is the activation energy,
R is The Gas constant = 8.31joules/mole and
T is Temperature in Kelvin.
Go solve it!
(If you get stuck, I made an attempt earlier in the responses – no guarantees on the correctness though).
Go materials engineering!
Damn it. I wish they woulda had the answer. I have this exact (word for word) same problem for my homework now haha.
So how come no one feels the problem might be that his teacher (possibly the TA depending on how “hands off” the professor is) is doing such a crappy job the students are resorting to Yahoo answers to learn this stuff?